> \NC\NC =\Im\int e^{(2+3i)x}\,dx\NR
> \NC\NC = \Im\Bigl(\frac{1}{2+3i}e^{(2+3i)}\Bigr)\NR
> \stopalign
> \stopformula
> From this we see that $\lim_{n\to+\infty}f(n)=0$.
> \stoptext
> %%%
>
> gives the attached ex1.pdf. As we can see the spacing inside \startalign
&
}\sin 3x\,dx\NC=\int\Im e^{(2+3i)x}\,dx\NR
\NC\NC =\Im\int e^{(2+3i)x}\,dx\NR
\NC\NC = \Im\Bigl(\frac{1}{2+3i}e^{(2+3i)}\Bigr)\NR
\stopalign
\stopformula
>From this we see that $\lim_{n\to+\infty}f(n)=0$.
\stoptext
%%%
gives the attached ex1.pdf. As we can see the spacing inside \startalign
\stopal
a
> \Set[size=3]{x\in\mathbb R~:~x^2=1}
> \stopformula
> \startformula
> \Set[size=4]{x\in\mathbb R~:~x^2=1}
> \stopformula
> \stopTEXpage
>
Many thanks for your answer, I appreciate it!
If you look at the example below (output attached), you see that
startformula
\{x\in\mathbb R~:~ x^2=1\}%Too small
\stopformula
\startformula
\bigl\{x\in\mathbb R~:~ x^2=1\bigr\}%I like this one
\stopformula
\startformula
\Bigl\{x\in\mathbb R~:~ x^2=1\Bigr\}%Too big
\stopformula
\getbuffer
\setupmathfence[Set][factor=1
; %%% Example file:
>
> \setupbodyfont[lucidaot]
>
> \definemathfence[Set][left="007B,right="007D,command=yes]
>
> \startbuffer
> \startformula
> \Set{x\in\mathbb R~:~x^2=1}
> \stopformula
> \stopbuffer
>
>
> \startTEXpage[offset=3bp]
>
> \st
rtTEXpage[offset=3bp]
\startformula
\{x\in\mathbb R~:~ x^2=1\}%Too small
\stopformula
\startformula
\bigl\{x\in\mathbb R~:~ x^2=1\bigr\}%I like this one
\stopformula
\startformula
\Bigl\{x\in\mathbb R~:~ x^2=1\Bigr\}%Too big
\stopformula
\getbuffer
\setupmathfence[Set][factor=1]%I like this one
\getbuffer
har"EEEFF$) indeed makes it look better between the $f$ and the
>>> parenthesis.)
>>>
>>> /Mikael
>>>
>>> %%%
>>> \setupbodyfont[bonum]
>>>
>>> \starttext
>>> \startTEXpage[offset=3bp]
>>> (Look at this $f$)
t
>> \startTEXpage[offset=3bp]
>> (Look at this $f$) and this $f$? (see also $k$?, $x$? and $z$?)
>>
>> There might be more problems (like between $t$ and the parenthesis in
>> $e^t$) is too small.
>>
>> The space between $dx$ and the bar is too small:
>>
x\,dx\Bigr|,
\stopformula
Look at the $f$ and the bar:
\startformula
\Bigl|\int f\Bigr|
\stopformula
The $x$ seems to be outside the fraction:
\startformula
\frac{a^2}{1-x}
\stopformula
We add another one (in fact two) including $f$:
\startformula
f\Bigl(\frac{a+b}{2}\Bigr)
\stopformula
Also look at $
(Look at this $f$) and this $f$? (see also $k$?, $x$? and $z$?)
There might be more problems (like between $t$ and the parenthesis in
$e^t$) is too small.
The space between $dx$ and the bar is too small:
\startformula
\Bigl|\int_0^\pi\sin x\,dx\Bigr|,
\stopformula
Look at the $f$ and the bar:
\startfo
{ name = "fourier-mlit.tfm", vector = "tex-mi",
>> skewchar=0x7F },
>> { name = "fourier-mlit.tfm", vector = "tex-it",
>> skewchar=0x7F },
>> { name = "fourier-mlb.tfm", vector = "tex-bf",
>> s
{ name = "fourier-ms.tfm", vector = "tex-sy",
> skewchar=0x30, parameters = true },
> { name = "fourier-mex.tfm", vector = "tex-ex", extension
> = true },
> msam,
> msbm,
x-ex", extension =
true },
msam,
msbm,
},
}
}
}
%%%
testfile.tex:
%%%
\loadtypescriptfile[type-fourier]
\setupbodyfont[fourier,12pt]
\starttext
\startTEXpage[offset=3bp]
Some math: $y''=(y')'$.
A displayed formula:
\startformula
f(x) =
er bugs being
>>>> resolved meanwhile):
>>>>
>>>> %%%
>>>> \starttext
>>>> %
>>>> Compare $f'$ to $(f')$ and to $f''$, $(f'')$, $f^{''}$ and $(f^{''})$.
>>>> %
>>>> \startformula
>>>> %
; resolved meanwhile):
>>>
>>> %%%
>>> \starttext
>>> %
>>> Compare $f'$ to $(f')$ and to $f''$, $(f'')$, $f^{''}$ and $(f^{''})$.
>>> %
>>> \startformula
>>>%
>>>\int\nolimits_a^b \bigl(\|f(x)\|\bigr)\, {\math
. You can verify that by using the
>> following minimal example (created to show some older bugs being resolved
>> meanwhile):
>>
>> %%%
>> \starttext
>> %
>> Compare $f'$ to $(f')$ and to $f''$, $(f'')$, $f^{''}$ and $(f^{''})$.
>>
imal example (created to show some older bugs being resolved
> meanwhile):
>
> %%%
> \starttext
> %
> Compare $f'$ to $(f')$ and to $f''$, $(f'')$, $f^{''}$ and $(f^{''})$.
> %
> \startformula
> %
> \int\nolimits_a^b \bigl(\|f(x)\|\bigr)\, {\ma
')$ and to $f''$, $(f'')$, $f^{''}$ and $(f^{''})$.
%
\startformula
%
\int\nolimits_a^b \bigl(\|f(x)\|\bigr)\, {\mathrm d}x
%
\stopformula
%
\stoptext
%%%
The output is attached. The primes are obviously rendered too small. And while
$f'$ seems to lead to a placement
the first one
is weird when using \frac and \setupmathradical[sqrt][alternative=default].
Best regards: OK
%%% start of test file
\starttext
\startbuffer[math]
\startformula
\sqrt{1+\Bigl(\frac{f(x_k)-f(x_{k-1})}{x_k-x_{k-1}}\Bigr)^2}
\stopformula
\startformula
1+\Bigl(\frac{f(x_k)-f(x_{k-1})}{x_k-x_{k
and \setupmathradical[sqrt][alternative=default].
Best regards: OK
%%% start of test file
\starttext
\startbuffer[math]
\startformula
\sqrt{1+\Bigl(\frac{f(x_k)-f(x_{k-1})}{x_k-x_{k-1}}\Bigr)^2}
\stopformula
\startformula
1+\Bigl(\frac{f(x_k)-f(x_{k-1})}{x_k-x_{k-1}}\Bigr)^2
\stopformula
\startformula
\sqrt
s is a bug:
%%% start of test file
\setupmathradical[sqrt][alternative=default]
\starttext
\startformula
\sqrt{1+\Bigl(\frac{f(x_k)-f(x_{k-1})}{x_k-x_{k-1}}\Bigr)^2}
\stopformula
\stoptext
%%% stop of test file
The n
\quad
\biggl\lvert \frac{a}{b} \biggr\rvert
\quad
\Bigl \lvert \frac{a}{b} \Bigr \rvert
\quad
\bigl \lvert \frac{a}{b} \bigr \rvert
\stopformula
\stoptext
___
If your question is of interest to others as well
On Tue, Aug 9, 2016 at 10:03 PM, Hans Hagen <pra...@wxs.nl> wrote:
> On 8/9/2016 9:31 PM, Mikael P. Sundqvist wrote:
>>
>> Hi!
>>
>> In the newest version (ConTeXt ver: 2016.08.08 21:28 MKIV beta fmt:
>> 2016.8.9 int: english/english) the document
>>
On 8/9/2016 9:31 PM, Mikael P. Sundqvist wrote:
Hi!
In the newest version (ConTeXt ver: 2016.08.08 21:28 MKIV beta fmt:
2016.8.9 int: english/english) the document
\starttext
$(1+1)$ and $\bigl(1+1\bigr)$ and $\Bigl(1+1\Bigr)$.
\stoptext
compiles to the attached file. For \big and \Big
Hello everyone,
How to insert more vertical space between the main items in the following
code ?
\def\point#1#2{$\bigl(#1\,;#2\bigr)$}
\def\vector#1{\vec{#1}}
\definemathmatrix
[pmatrix]
[left={\left(\,},right={\,\right)}]
\starttext
\startitemize[n][stopper={.},style=bold,color=darkred
On 2016-02-24 19:19:19 +, Hans Hagen said:
On 2/24/2016 5:48 PM, Nicola wrote:
I have a problem with the symbol in the subject. This is a
minimal document:
\starttext
$\llbracket x\rrbracket$
$\bigl\llbracket x\bigr\rrbracket$
$\Bigl\llbracket x\Bigr\rrbracket$
$\biggl\llbracket x\biggr
On 2/24/2016 5:48 PM, Nicola wrote:
I have a problem with the symbol in the subject. This is a
minimal document:
\starttext
$\llbracket x\rrbracket$
$\bigl\llbracket x\bigr\rrbracket$
$\Bigl\llbracket x\Bigr\rrbracket$
$\biggl\llbracket x\biggr\rrbracket$
$\Biggl\llbracket x\Biggr\rrbracket
I have a problem with the symbol in the subject. This is a
minimal document:
\starttext
$\llbracket x\rrbracket$
$\bigl\llbracket x\bigr\rrbracket$
$\Bigl\llbracket x\Bigr\rrbracket$
$\biggl\llbracket x\biggr\rrbracket$
$\Biggl\llbracket x\Biggr\rrbracket$
\stoptext
Using ConTeXt from TeX Live
In fact, you are both right, write the macro differently.
\def\repere{\bigl(O\,;I,J\bigr)}
\starttext
\dorecurse{2}{blabla} $\repere$ \dorecurse{2}{blabla}
\dorecurse{2}{blabla} $\bigl(O\,;I,J\bigr)$ \dorecurse{2}{blabla}
\stoptext
Thanks,
Fabrice
2015-08-27 13:32 GMT+02:00 Peter Münster
On 8/27/2015 2:39 PM, Fabrice Couvreur wrote:
In fact, you are both right, write the macro differently.
\def\repere{\bigl(O\,;I,J\bigr)}
\starttext
\dorecurse{2}{blabla} $\repere$ \dorecurse{2}{blabla}
\dorecurse{2}{blabla} $\bigl(O\,;I,J\bigr)$ \dorecurse{2}{blabla}
\stoptext
you can add
{\bigl(O\,;I,J\bigr)}
\starttext
\dorecurse{2}{blabla} $\repere$ \dorecurse{2}{blabla}
\dorecurse{2}{blabla} $\bigl(O\,;I,J\bigr)$ \dorecurse{2}{blabla}
\stoptext
you can add \autoinsertnextspace to macros
Thanks,
Fabrice
2015-08-27 13:32 GMT+02:00 Peter Münster pmli...@free.fr
Hi Otared,
I did not know it because, before migrating to context, I used latex with
this : \newcommand{\repere}{$\bigl(O\,;I,J\bigr)$.
It's not very convenient to add \ every time !
Thanks,
Fabrice
2015-08-27 11:30 GMT+02:00 Otared Kavian ota...@gmail.com:
Hi Fabrice,
This is a normal
, as in the following example:
\define\repere{$\bigl(O\,;I,J\bigr)$\space}
\starttext
\dorecurse{2}{blabla} \repere \dorecurse{2}{blabla}
Déterminer la trajectoire dans le repère \repere\unskip.
\dorecurse{2}{Blabla} \repere\ \dorecurse{2}{blabla}
\dorecurse{2}{blabla} $\bigl(O\,;I,J\bigr)$ \dorecurse{2
On Thu, Aug 27 2015, Fabrice Couvreur wrote:
I did not know it because, before migrating to context, I used latex with
this : \newcommand{\repere}{$\bigl(O\,;I,J\bigr)$.
In LaTeX there is no space neither:
--8---cut here---start-8---
\newcommand{\repere
not create a space between the closing delimiter and
the following text, why ?
Thanks,
Fabrice
\def\repere{$\bigl(O\,;I,J\bigr)$}
\starttext
\dorecurse{2}{blabla} \repere \dorecurse{2}{blabla}
\dorecurse{2}{blabla} $\bigl(O\,;I,J\bigr)$ \dorecurse{2}{blabla}
\stoptext
Hi,
The macro \repere does not create a space between the closing delimiter and the
following text, why ?
Thanks,
Fabrice
\def\repere{$\bigl(O\,;I,J\bigr)$}
\starttext
\dorecurse{2}{blabla} \repere \dorecurse{2}{blabla}
\dorecurse{2}{blabla} $\bigl(O\,;I,J\bigr)$ \dorecurse{2}{blabla
the `d` in calculus should be
typeset. There are also \differentiald and \differentialD that map to
unicode slots.
\definemathcommand[arsinh][nolop]{\mathlabel{arsinh}}
\starttext
$\arsinh z = \ln\bigl(z + \sqrt{z^2 + 1}\bigr)$\par
$\rho_{\mathlabel{air}} = \frac{p}{R_{\mathlabel{specific}}T
and
consistent way to label its math objets (functions and variables with
subscripts):
\definemathcommand[arsinh][nolop]{\mathlabel{arsinh}}
\starttext
$\arsinh z = \ln\bigl(z + \sqrt{z^2 + 1}\bigr)$\par
$\rho_{\mathlabel{air}} = \frac{p}{R_{\mathlabel{specific}}T}$\par
\stoptext
Hans Hagen wrote
{}}
With this new \mathlabel command, the user now have a convenient and
consistent way to label its math objets (functions and variables with
subscripts):
\definemathcommand[arsinh][nolop]{\mathlabel{arsinh}}
\starttext
$\arsinh z = \ln\bigl(z + \sqrt{z^2 + 1}\bigr)$\par
$\rho_{\mathlabel{air
Dear members,
Why the floor and ceil math delimiters don't display?
Code:
\starttext
\startformula
\Bigl\lfloor \frac{x}{y}\Bigr\rfloor
\stopformula
\startformula
\Bigl\lceil \frac{x}{y}\Bigr\rceil
\stopformula
\stoptext
Thank you in advance.
Maggyero
Mr Hagen, is it the expected behaviour?
\starttext
The delimiters are correctly displayed:
\startformula
\left\lfloor \frac{x}{y}\right\rfloor
\stopformula
The delimiters vanish:
\startformula
\Bigl\lfloor \frac{x}{y}\Bigr\rfloor
\stopformula
\stoptext
Maggyero
MWE:
\starttext
The delimiters are correctly displayed:
\startformula
\left\lfloor \frac{x}{y}\right\rfloor
\stopformula
The delimiters vanish:
\startformula
\Bigl\lfloor \frac{x}{y}\Bigr\rfloor
\stopformula
\stoptext
Maggyero
Dear NTG-ConTeXt members,
The math delimiters for floor and ceiling functions (\lfloor, \rfloor,
\lceil, \rceil) work with the automatic scaling commands (\left and \right)
but vanish with the manual scaling commands (\big, \Big, \bigg, \Bigg,
\bigl, \Bigl, \biggl, \Biggl, \bigr, \Bigr, \biggr
Dear Hans,
I‘m afraid that beta from today doesn’t compile what beta from tow days
ago compiled.
Here is the minimal sample:
\starttext
\startformula
\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr)
\stopformula
\stoptext
Many thanks for your help,
Pablo
--
http://www.ousia.tk
Hi,
I have two problems with vertical position, one in itemize and one in
math. The example below show them both.
\starttext
\startitemize[n]
\item
\startitemize[a][left={},right={)},stopper=]
\item Bla bla
$\theta = \arctan\bigl(\frac{\bar{y}^2}{\bar{x}^2}\bigr)$ % comment
this line out to see
be equivalent to \Vert? (That is not wanted)
* Will it be possible to write \Bigl|| and \Bigr|| to scale both bars
to other sizes?
* What if one would like to have three bars with the same spacing
between the bars as in \Vert?
/Mikael
in the middle be equivalent to \Vert? (That is not wanted)
The proper way to lay this out is with a little whitspace between
the to values, so input should be |z| |w| and not as |z||w| !
* Will it be possible to write \Bigl|| and \Bigr|| to scale both bars
to other sizes?
* What
WartoÅÄ oczekiwana wynosi
\startformula
k(\tfrac{1}{6^2}1+\cdots+\tfrac{1}{6^2}6)
+\bigl(\tfrac{1}{6}(k+1)+\cdots+\tfrac{1}{6}6\bigr)
=\tfrac{1}{12}(-k^2+6k+42),
\stopformula
a~wiÄc osiÄ
ga maksimum dla \math{k_{\rm
]
\startalignment[middle]
If $C\subset\overbar{D}$ is countable and
$C\subset\clconv\bigl(\{0\}\cup F(C)\bigr)$, then
$\overbar{C}$ is compact.
\stopalignment
\blank[small]
Is there any option for alignment which would enable me not to put the
blanks manually?
TIA,
--
Marcin Borkowski
http
} if the
following implication holds:
\blank[small]
\startalignment[middle]
If $C\subset\overbar{D}$ is countable and
$C\subset\clconv\bigl(\{0\}\cup F(C)\bigr)$, then
$\overbar{C}$ is compact.
\stopalignment
\blank[small]
Is there any option for alignment which would enable me
but then found out that the | has
round tops (ok, i could use pdf literals to draw lines but not today)
2) The horizontal spacing in the \big version seems to be bigger than
for the \bigl/\bigr version (and similar for \Big vs \Bigl/\Bigr). I'd
expect the same spacing (the l and r are just
to be bigger than
for the \bigl/\bigr version (and similar for \Big vs \Bigl/\Bigr). I'd
expect the same spacing (the l and r are just there for the writer to
easily see what is left and what is right).
repaired .. (i also added \plainbigmathmode
3) I'd expect that \| gives double bars, like
On 8-4-2010 10:37, Mikael Persson wrote:
Thanks for you answer and explanation. Is there a reason why you do
not add \| to get double bars? This is the way it is done in LaTeX
(OK, not really an argument). I'm just curious.
we never had \| in mkii and in mkiv it's equivalent to | (just like
{$|x|^n$} % as expected.
\foo{$\bigl|x^n\bigr|$} % expect bigger bars
\foo{$\big|x^n\big|$} % expect bigger bars
\foo{$\Bigl|x^n\Bigr|$} % too small again (but bigger than \big)
\foo{$\biggl|x^n\biggr|$} % too small again (but bigger than \big)
\foo{$\Biggl|x^n\Biggr|$} % too small again
Dear list,
I have problems with \big, \bigl, \Bigl, ...
%% Example
\def\foo#1{\type{#1}: #1}
\starttext
\foo{$|x|^n$} % as expected.
\foo{$\bigl|x^n\bigr|$} % expect bigger bars
\foo{$\big|x^n\big|$} % expect bigger bars
\foo{$\Bigl|x^n\Bigr|$} % too small again (but bigger than \big)
\foo
On 6-4-2010 10:30, Mikael Persson wrote:
Dear list,
I have problems with \big, \bigl, \Bigl, ...
%% Example
\def\foo#1{\type{#1}: #1}
\starttext
\foo{$|x|^n$} % as expected.
\foo{$\bigl|x^n\bigr|$} % expect bigger bars
\foo{$\big|x^n\big|$} % expect bigger bars
\foo{$\Bigl|x^n\Bigr
On Tue, Apr 6, 2010 at 4:43 PM, Hans Hagen pra...@wxs.nl wrote:
On 6-4-2010 10:30, Mikael Persson wrote:
Dear list,
I have problems with \big, \bigl, \Bigl, ...
%% Example
\def\foo#1{\type{#1}: #1}
\starttext
\foo{$|x|^n$} % as expected.
\foo{$\bigl|x^n\bigr|$} % expect bigger bars
On Fri, Nov 13, 2009 at 4:03 AM, Mojca Miklavec
mojca.miklavec.li...@gmail.com wrote:
Hello,
I have tried to compile an old document (written in mkii times). Among
other problems that I yet need to isolate, the following minimal
example doesn't want to compile: $\bigl| x \bigr$ since
| x \bigr$ since | aren't
recognized as candidates for delimiters. There is a workaround of
course (using \langle, \rangle, ... instead of ), but the three
characters are just way too handy to use.
| works fine here. and don't. I did not know that \left is equivalent
to \left\langle even in plain
minimal
example doesn't want to compile: $\bigl| x \bigr$ since | aren't
recognized as candidates for delimiters. There is a workaround of
course (using \langle, \rangle, ... instead of ), but the three
characters are just way too handy to use.
| works fine here. and don't. I did not know
Hello,
I have tried to compile an old document (written in mkii times). Among
other problems that I yet need to isolate, the following minimal
example doesn't want to compile: $\bigl| x \bigr$ since | aren't
recognized as candidates for delimiters. There is a workaround of
course (using \langle
(A)$, $r_i, s_j \in R$, on aquestes igualtats són
dins el grup lliure $F(A)$. Com que $w = u v$ també dins el grup lliure, tenim
que
\placeformula[-] \startformula \startsplit
\NC w = u v \NC = \bigl( \prod_{i = 1}^N x_i^{-1} r_i x_i \bigr) \cdot \bigl(
\prod_{j=1}^M y_j^{-1} s_j y_j \bigr) \NR
igualtats són dins el grup lliure $F(A)$. Com que $w = u v$ també dins
el grup lliure, tenim que
\placeformula[-] \startformula \startsplit
\NC w = u v \NC = \bigl( \prod_{i = 1}^N x_i^{-1} r_i x_i \bigr) \cdot
\bigl( \prod_{j=1}^M y_j^{-1} s_j y_j \bigr) \NR
\NC \NC = (x_1^{-1} r_1 x_1)\cdots
, s_j \in R$, on aquestes
igualtats són dins el grup lliure $F(A)$. Com que $w = u v$ també dins
el grup lliure, tenim que
\placeformula[-] \startformula \startsplit
\NC w = u v \NC = \bigl( \prod_{i = 1}^N x_i^{-1} r_i x_i \bigr)
\cdot \bigl( \prod_{j=1}^M y_j^{-1} s_j y_j \bigr) \NR
\NC \NC
]
\startformula
\pauli = \dirac^2 = \Bigl(\sum_{j=1}^2 \sigma_j\big(-i\PD{}{x^j}-a_j\big)\Bigr)^2 =
\startpmatrix
\NC 0 \NC \cre \NR
\NC \ann \NC 0\NR
\stoppmatrix^2
\stopformula
from which it follows that it is a non-negative operator. Now let us be more precise about the domains. As in the case
On Sat, Aug 23, 2008 at 5:58 AM, Eric DÉTREZ [EMAIL PROTECTED] wrote:
Hello
The bigl, bigr ans so on are really BIG (huge even) when used with
lucida.
I think that math-lbr is guilty : it says
**
\def\LBRbig {\@@dobig{8.20}}
\def\LBRBig {\@@dobig
Le 29 août 08 à 12:00, Yue Wang a écrit :
On Sat, Aug 23, 2008 at 5:58 AM, Eric DÉTREZ [EMAIL PROTECTED] wrote:
Hello
The bigl, bigr ans so on are really BIG (huge even) when used with
lucida.
I think that math-lbr is guilty : it says
**
\def
Are you sure? see the first line of the attachment.
On Sat, Aug 23, 2008 at 5:58 AM, Eric DÉTREZ [EMAIL PROTECTED] wrote:
Hello
The bigl, bigr ans so on are really BIG (huge even) when used with
lucida.
I think that math-lbr is guilty : it says
Hello
The bigl, bigr ans so on are really BIG (huge even) when used with
lucida.
I think that math-lbr is guilty : it says
**
\def\LBRbig {\@@dobig{8.20}}
\def\LBRBig {\@@dobig{10.80}}
\def\LBRbigg {\@@dobig{13.42}}
\def\LBRBigg {\@@dobig{16.03}}
\def
On Mon, 17 Apr 2006, Hans Hagen wrote:
well, i traced back the way this brace ends up in the pdf file and this
is what i observe:
- the antt and cm ex tfm files have exactly the same values (although
antt is 7 bit safe)
- so the problem must be in the map file and/or encoding
- and,
Aditya Mahajan wrote:
So shall I send a bug report to them with a summary of this thread or
have you already done that?
i cd'd Jacko and Janusz so it's ok
Hans
-
Hans Hagen | PRAGMA
Mojca Miklavec wrote:
Hans Hagen wrote:
Mojca Miklavec wrote:
On 4/14/06, Hans Hagen wrote:
Aditya Mahajan wrote:
Hi,
\bigr\} does not give me anything while using antykwa fonts. \big\}
also does not work. \right\} works correctly. Is there something
Hans Hagen wrote:
Mojca Miklavec wrote:
On 4/14/06, Hans Hagen wrote:
Aditya Mahajan wrote:
Hi,
\bigr\} does not give me anything while using antykwa fonts. \big\}
also does not work. \right\} works correctly. Is there something
missing in the typescripts? I have no idea on how
Aditya Mahajan wrote:
Hi,
\bigr\} does not give me anything while using antykwa fonts. \big\}
also does not work. \right\} works correctly. Is there something
missing in the typescripts? I have no idea on how fonts work, so can
not debug the problem.
\usetypescript
[antykwa
Hi,
\bigr\} does not give me anything while using antykwa fonts. \big\}
also does not work. \right\} works correctly. Is there something
missing in the typescripts? I have no idea on how fonts work, so can
not debug the problem.
\usetypescript
[antykwa-torunska][ec]
\setupbodyfont
\mapdown\phi\mapdown\psi\cr
0\mapright{}{\cal O}_C\mapright{}
\pi_*{\cal O}_D\mapright\delta
R^1f_*{\cal O}_V(-D)\mapright{}0\cr
\mapdown{\theta_i\otimes\gamma^{-1}}\cr
\hidewidth R^1f_*\bigl({\cal O}
_V(-iM)\bigr)\otimes\gamma^{-1}\hidewidth\cr
\mapdown{}\cr
0\cr}$$
Since i'm just a newbie
\mapdown\phi\mapdown\psi\cr
0\mapright{}{\cal O}_C\mapright{}
\pi_*{\cal O}_D\mapright\delta
R^1f_*{\cal O}_V(-D)\mapright{}0\cr
\mapdown{\theta_i\otimes\gamma^{-1}}\cr
\hidewidth R^1f_*\bigl({\cal O}
_V(-iM)\bigr)\otimes\gamma^{-1}\hidewidth\cr
\mapdown{}\cr
0\cr}$$
Since i'm just a newbie of TeX, I
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